In triangleABC and triangle DEF, AB = DE , AB parallel DE, BC = EF. Vertices A,B and C are joined to vertices D,E and F respectively . Show that triangle ABC congruent to triangle DEF.
Answers
Answered by
19
The question has BC parallel EF
Prove ABED is a parallelogram with AB= DE and AB parallel DE
Then prove BEFC is a parallelogram with BC= EF and BC parallel EF
Then AD parallel BE and CF parallel BE and AD = BE and BE = CF ( ABED and BEFC is a parallelogram)
Therefore ACFD is a parallelogram with AD parallel CF and AD= CF
In triangle ABC and DEF
AB = DE (given)
BC = EF (given)
AC = DF (ACDF is a parallelogram)
Triangle ABC is congruent to triangle DEF by SSS rule
Prove ABED is a parallelogram with AB= DE and AB parallel DE
Then prove BEFC is a parallelogram with BC= EF and BC parallel EF
Then AD parallel BE and CF parallel BE and AD = BE and BE = CF ( ABED and BEFC is a parallelogram)
Therefore ACFD is a parallelogram with AD parallel CF and AD= CF
In triangle ABC and DEF
AB = DE (given)
BC = EF (given)
AC = DF (ACDF is a parallelogram)
Triangle ABC is congruent to triangle DEF by SSS rule
Answered by
11
Answer:
here is your answer in the photo.
Attachments:
Similar questions