In triangleABC , D and E points on the sides AB and AC respectively. For each of the
following cases show that DE II BC:
(1) AB = 12 cm, AD = 8 cm, AE = 12 cm and AC = 18 cm
Answers
Answered by
4
Step-by-step explanation:
In triangle ABC
AD = 8cm. AB = 12 cm.
therefore BD = AB- AD
=12 -8 = 4cm.
BD =4cm.
AE= 12cm. AC = 18cm.
therefore EC = AC - AE
=18 - 12 = 6 cm.
AD/DB = 8/4 = 2/1
AE/EC = 12/6 = 2/1
BY BASIC PROPORTIONALITY THEOREM
AD / DB =AE / EC
IMPLIES THAT DE II BC ☺
Attachments:
Similar questions