In triangleABC,E is rge midpoint of median AD &BE produced meets side AC at point Q. Show BE:EQ=3:1
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Step-by-step explanation:
Let's take point x on AC such that BQ∣∣DX
CD=DB (D is median)
Applying midpoint theorem in ΔCBQ
2DX=BQ
Also AE=ED (E is midpoint of AD)
Now applying midpoint theorem on ΔDAX.
2EQ=DX
Hence
EQ
BE
=
EQ
BQ−EQ
=
2
DX
2DX−
2
DX
=
DX
3DX
=3:1
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