Question

In triangleABC,it is given that angle C =90° and tan A =1/√3 ,find the value of (sinA cosB+cosA sinB)

Answer 1

the answer for this question is 1 explation given below

Answer 2

Answer:

1

Step-by-step explanation:

Given : -

Tan A = 1 / √3

As We Know , Tan 30° is 1 / √ 3

Therefore ; Angle A = 30°

& A/Q : -

Angle C = 90° ,

Therefore ; Angle B = 180 ° - ( 90° + 30° )

{ As We know , Sun of All three angles of a ∆ Is equal to 180° )

Angle B = 180° - 120° = 60 °

Now ,

Sin A Cos B + CosA Sin B

=> Sin 30° Cos 60° + Cos 30° Sin 60°

=> 1/2 × 1/2 + √3 / 2 × √ 3/ 2

=> 1 / 4 + 3 / 4

=> 4 / 4

=> 1