In trianglePQR, the bisector of angleQ and angleR intersect at I. if angle P=70,then find m angleQIR
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in ∆ PQR
angle p+angle Q+angle R=180°(angle sum property)
70+angle Q+angle R=180°
angle Q+angle R=180°-70°
=110°
now,in ∆QIR
1/2 angleQ +1/2 angle R+angle QIR=180°(angle sum property of a∆)
1/2(angle Q+ angle R)+angle QIR=180°
1/2(110°)+ angle QIR=180°
55°+angle QIR=180°
angle QIR=180°-55°
angle QIR=125°
hope it helps
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