Question

In triangles ABC and PQR, if ABC ~ PQR, A = 54° and Q = 62°, then find the value of (C + R).

Answer 1

as we know that,

ABC~PQR So,

A=P=54°

B=Q=62°

C=R=?

BY ANGLE SUM PROPERTY

54°+62°+x=180°

116°+x= 180°

x=180°-116°

x=64

so,

C=R=64

so

C+R=64+64

C+R=128π