Question

In two alloys the ratio of iron and copper is 4 ratio 3 and 6 ratio 1 respectively if 14 kg of the first Roy and 42 kg of the second all is mixed together to form a new law and what will be the ratio of iron to copper in the new alloy

Answer 1

Solution:

 In 14 Kg of first Alloy, Ratio of iron and copper=4 :3

Let ratio of Iron and copper in first alloy be , 4 x and 3 x.

  4 x + 3 x= 14

7 x =14

Dividing both sides by, 2 gives

x=2

So, Amount of Iron = 4 × 2= 8 Kg

Amount of Copper = 3 × 2= 6 Kg

 In 14 Kg of Second Alloy, Ratio of iron and copper=6:1

Let ratio of Iron and copper in first alloy be , 6 x and 1 x.

  6 x + 1 x= 42

7 x =42

Dividing both sides by, 7 gives

x=6

So, Amount of Iron = 6 × 6= 36 Kg

Amount of Copper = 6 × 1= 6 Kg

When two Alloys are Mixed total amount of Alloy=42 Kg + 14 Kg

                             =56 Kg

Total Amount of Iron in Combination of two Alloy = 36 +8=44 Kg

Total Amount of Copper in Combination of two Alloy = 6 +6=12 Kg

Ratio of Iron to copper in the new alloy

                    $=\frac{44}{12}\\\\=\frac{11}{3}$

  =11 : 3    

Answer 2

Answer:

11:3

Step-by-step explanation:

By the method of alligation.