in two complementary angles one of the angle is four times the remaining angle then find the two complementary angles
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let the angle be y.
remaining angle = 90-y
4 times the remaining angle= 4(90-y) = 360-4y
ATQ, 360-4y+y = 90
-3y = 90-360
-3y = -270
y= -270/-3
y=90
remaining angle = 360-4y = 360-4(90) = 0
remaining angle = 90-y
4 times the remaining angle= 4(90-y) = 360-4y
ATQ, 360-4y+y = 90
-3y = 90-360
-3y = -270
y= -270/-3
y=90
remaining angle = 360-4y = 360-4(90) = 0
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