Question

In two dice game, the player take turns to roll both dice, they can roll as many times as they want

in one turn. A player scores the sum of the two dice thrown and gradually reaches a higher score as

they continue to roll. If a single number 1 is thrown on either die, the score for that whole turn is

lost. Two dice are thrown simultaneously

37. What is the probability of getting the sum as an even number ?

(i) ¾ (ii) 1/2 (iii) 1/4 (iv) 5/8

38. What is the probability of getting the sum as a prime number ?

(i) 5/12 (ii) 1/6 (iii) 7/12 (iv) 11/12

39. What is the probability of getting the sum of at least 10?

(i) 5/12 (ii) 5/6 (iii) 1/6 (iv) 7/12

40. What is the probability of getting a doublet of even number ?

(i) 1/12 (ii) 5/12 (iii) 11/12 (iv) 7/12

41. What is the probability of getting a product of numbers greater than 16?

(i) 7/36 (ii) 2/9 (iii) 1/4 (iv) 11/36​

Answer 1

Answer:

a,a,b,c, this is correct answer in your question

Answer 2

Answer :-

we know that, when two dice are tossed once, then possible events will be :-

• (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
• (2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
• (3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
• (4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
• (5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
• (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
• Total outcomes = 36 .

so,

→ The Possible outcomes of getting the sum as an even number = (1,1) , (1,3) , (1,5), (2,2) (2,4) , (2,6) ________ (6,6) = Total 18 .

then,

→ Required probability = 18/36 = (1/2) (Ans.ii)

now,

→ The Possible outcomes of getting the sum as an prime number = 2, 3, 5 ,7 and 11 as sum = Total = 4 + 3 + 2 + 2 + 2 + 2 = 15

then,

→ Required probability = 15/36 = (5/12) (Ans.i)

now,

→ The Possible outcomes of getting the sum of a least number = (4,6) , (5,5) , (5,6), (6,4) (6,5) , (6,6) = Total 6 .

then,

→ Required probability = 6/36 = (1/6) (Ans.iii)

now,

→ The Possible outcomes of getting doublet of even number = (2,2) , (4,4) , (6,6) = Total 3 .

then,

→ Required probability = 3/36 = (1/12) (Ans.i)

now,

The Possible outcomes of getting the product greater than 16 = (3,6) , (4,5) , (4,6), (5,4) (5,5) , (5,6) ________ (6,6) = Total 10 .

then,

→ Required probability = 10/36 = (5/18) (Ans.)

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