Question

In two different polar molecules, the ionic charge is 9.6 x 10^-10 esu and 3.2 x 10^-19 c respectively. if inter ionic distance in both the molecule is 1a° unit, then the dipole moment are respectively

Answer 1

dipole moment of a molecule can be calculated as:

$dipole moment= q \times d$

Here, q denotes charge

       d denotes distance

So dipole moment for the first molecule is:

$9.6  \times10^-10 esu \times 1 A^{0}$

=9.6 x 10⁻¹⁰ debye

So dipole moment for the second molecule is:

$3.2 \times 10^-19 c {0} =9.59 \times  10^-10 esu$

$9.59 \times 10^-10 esu \times 1 A^{0}$  

=9.59 debye

Answer 2

Answer:

9.59 debye is the exact answer