Question

In two triangles DEF and PQR, if DE = QR, EF = PR and FD = PQ, then​

Answer 1

Answer:

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Step-by-step explanation:

In two triangles DEF and PQR, if DE = QR, EF = PR and FD = PQ, then​

Given:  PR=EF, QR=DE and PQ=FD

Now, In △PRQ and △DEF

PR=EF

QR=DE

PQ=FD

Thus, △PQR≅△FDE (SSS rule).

Answer 2

Given:

In two triangles DEF and PQR, DE = QR, EF = PR and FD = PQ.

To find:

The relationship between the given triangles DEF and PQR.

Solution:

As we know that in a triangle ABC and DEF if all the sides of a triangle ABC are equal to the corresponding sides of another triangle DEF then triangle ABC and DEF are said to be congruent by the side-side-side (SSS) rule.

i.e.

If AB = DE, BC = EF and AC = DF then ABC ≅ DEF.

Now,

According to the question, we have two triangles DEF and PQR where DE = QR, EF = PR and FD = PQ

So, using the above property of congruence of triangles, we have,

Triangle DEF is congruent to triangle QRP by the SSS rule.

Hence, triangle DEF ≅ triangle QRP.