Question

in usual notation the acceleration due to gravit at a height h from the surface of the earth is....? ​

Answer 1

• the usual notation, the acceleration due to gravity at a height h from. the surface of the earth is. GM. (a) 8- (R+h)

Answer 2

__Hey mete here is your answers__

The gravitational acceleration at height "h" is

The gravitational acceleration at height "h" isg = GM/(R +h)^2

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.F = GMm/d^2

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.F = GMm/d^2Here

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.F = GMm/d^2HereM = mass of the earth

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.F = GMm/d^2HereM = mass of the earthm = mass of the stone

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.F = GMm/d^2HereM = mass of the earthm = mass of the stoned = distance

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.F = GMm/d^2HereM = mass of the earthm = mass of the stoned = distanceF = mg

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.F = GMm/d^2HereM = mass of the earthm = mass of the stoned = distanceF = mgSo

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.F = GMm/d^2HereM = mass of the earthm = mass of the stoned = distanceF = mgSomg = GMm/d^2

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.F = GMm/d^2HereM = mass of the earthm = mass of the stoned = distanceF = mgSomg = GMm/d^2Or

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.F = GMm/d^2HereM = mass of the earthm = mass of the stoned = distanceF = mgSomg = GMm/d^2Org = GM/d^2

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.F = GMm/d^2HereM = mass of the earthm = mass of the stoned = distanceF = mgSomg = GMm/d^2Org = GM/d^2Suppose the object is on the surface of the earth or nearby.

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.F = GMm/d^2HereM = mass of the earthm = mass of the stoned = distanceF = mgSomg = GMm/d^2Org = GM/d^2Suppose the object is on the surface of the earth or nearby.Now, in this case, d = R+ h

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.F = GMm/d^2HereM = mass of the earthm = mass of the stoned = distanceF = mgSomg = GMm/d^2Org = GM/d^2Suppose the object is on the surface of the earth or nearby.Now, in this case, d = R+ hg = GM/(R +h)^2

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.F = GMm/d^2HereM = mass of the earthm = mass of the stoned = distanceF = mgSomg = GMm/d^2Org = GM/d^2Suppose the object is on the surface of the earth or nearby.Now, in this case, d = R+ hg = GM/(R +h)^2Hence the gravitational acceleration at height "h" is g = GM/(R +h)^2.

The gravitational acceleration at height "h" isg = GM/(R +h)^2Explanation:Force between two objects is given by the universal law of gravitation.F = GMm/d^2HereM = mass of the earthm = mass of the stoned = distanceF = mgSomg = GMm/d^2Org = GM/d^2Suppose the object is on the surface of the earth or nearby.Now, in this case, d = R+ hg = GM/(R +h)^2Hence the gravitational acceleration at height "h" is g = GM/(R +h)^2.Read more on Brainly.in - https://brainly.in/question/13738054#readmore