In virtual memory system size of virtual address is ,32 bit, size of physical address is 30 bit, page size is 4 kbyte and size of each page table entry is 32 bit. The main memory is byte addresable .Find the maximum number of bits that can be used for storing protection and other information in each page table entry.
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0
Explanation:
Assuming a 4GB (2^32 byte) virtual and physical address space and a page size of 4kB (2^12 bytes), we see that the the 2^32 byte address space must be split into 2^20 pages.
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3
Answer:
In a virtual memory system, size of the virtual address is 32-bit, size of the physical address is 30-bit, page size is 4 Kbyte and size of each page table entry is 32-bit. The main memory is byte addressable. Which one of the following is the maximum number of bits that can be used for storing protection and other information in each page table entry?
2
10
12
14
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