Question

In what ratio does the x Asia divide the line segment joining the points (-4,-6) and (-1,7)?? Find the coordinate of the point of division.

Answer 1

Let x-axis divides the line segment joining (–4 , –6) and (–1, 7) at the point P in the ratio 1 : k. Now, coordinates of point of division P are. x coordinate = (-1 - 4k) / (k + 1). y ...

Answer 2

Answer:

The coordinate of the point of division is $(\frac{-34}{13},0)$.

Step-by-step explanation:

The line segment joint the points (-4,-6) and (-1,7).

Let the coordinate of the point of division be (x,0) and the division ratio is k:1.

Using section formula,

$0=\frac{k(7)+1(-6)}{k+1}$

$0=\frac{7k-6}{k+1})$

$7k-6=0$

$7k=6$

$k=\frac{6}{7}$

The division ratio is 6:7.

Using section formula the coordinate of the point of division is

$x=\frac{6(-1)+7(-4)}{6+7}$

$x=\frac{-6-28}{13}$

$x=\frac{-34}{13}$

The coordinate of the point of division is $(\frac{-34}{13},0)$.