In what ratio does the X-axis divide the line segment joining the points (2,-3)and (5,6)? find the coordinate of the point of intersection
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Answered by
16
Hey
Here is ur answer
Point lie on x -axis so its ordinate is 0
So
The coordinate of that point is (x,0)
now
We know that
x = M1x2 +M2x1/M1+ M2
And
y = M1y2 + M2y1/M1 +M2
But we know that y=0
So
0 =6M1-3M2/M1 + M2
0 = 6M1 -3M2
-6M1 = -3M2
M1/M2 = 1/2
The ratio is 1 ratio. 2
x = 1*5 +2*2/1+3 = 5+4 /3 =9/3 =3 The coordinate is (3,0)
Here is ur answer
Point lie on x -axis so its ordinate is 0
So
The coordinate of that point is (x,0)
now
We know that
x = M1x2 +M2x1/M1+ M2
And
y = M1y2 + M2y1/M1 +M2
But we know that y=0
So
0 =6M1-3M2/M1 + M2
0 = 6M1 -3M2
-6M1 = -3M2
M1/M2 = 1/2
The ratio is 1 ratio. 2
x = 1*5 +2*2/1+3 = 5+4 /3 =9/3 =3 The coordinate is (3,0)
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5
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