In what ratio is the segment joining (-1,-12) and (3,4) divided by the x-axis?
Answers
Answered by
5
Hi there......
Let the ratio = m:n
Let the point = X(x,0)
X(x,0)=[(-1)n+3m]/m+n,[(-12)n+4m]/m+n
=>0=[-12n+4m]/m+n
=>0=-12n+4m
12n=4m
n:m=4:12
n:m=1:3
Hence m:n=3:1
Please comment if any doubt....
And please mark my answer as the brainliest!!!
Let the ratio = m:n
Let the point = X(x,0)
X(x,0)=[(-1)n+3m]/m+n,[(-12)n+4m]/m+n
=>0=[-12n+4m]/m+n
=>0=-12n+4m
12n=4m
n:m=4:12
n:m=1:3
Hence m:n=3:1
Please comment if any doubt....
And please mark my answer as the brainliest!!!
Similar questions