Question

In what ratio is the segment joining the points A(6, 3) and B(–2, –5) divided by the x-axis

Answer 1

Let the points be A(6,3) , B(-2,-5) & (x,0) . Let the ratio be k:1 .

Step-by-step explanation:

(x,y) = (m1x2+m2x1/m1+m2 , m1y2+m2y1/m1+m2)

= (k×-2+1×6/k+1 , k×-5+1×3/k+1)

= (-2k+6/k+1 , -5k+3/k+1)

This point lies on the axis and we know that on the x-axis the coordinate of y-axis is zero .

-5k+3 = 0

k+1 1

let let's make cross multiplication .

-5k+3 = 0

-5k = -3

Now minus get cancelled in both LHS and RHS .

5k = 3

k = 3

5

k = 0•6

=> So that the ratio is 0•6:1 .