Question

In what ratio should tea worth rupees 10per kg be mixed with tea worth rupees 14 per kg so that the average price of the mixture may be rupees 11 per kg?

Answer 1

let the ratio of tea worth RS. 10 and 14 is x:y;

so average price is (10x+14y)/2 = 11;

10x + 14y = 22;

10:14 = x:y;

x = 10y/14;

putting this value in above equation we get

(100y/14) + 14y = 22;

100 y + 196Y = 318;

296y = 318;