Question

In what ratio will a point x axis divide the line segment joining (2,-3) and (5,6) also find the point on x axis

Answer 1

Step-by-step explanation:

Given x-axis divide the segment joining points

(2,−3) and (5,6)

Let the ratio be k:1

then x =  

m  

1

​  

+m  

2

​  

 

m  

1

​  

x  

2

​  

+m  

2

​  

x  

1

​  

 

​  

 

y=  

m  

1

​  

+m  

2

​  

 

m  

1

​  

y  

2

​  

+m  

2

​  

y  

1

​  

 

​  

=0

⇒  

k+1

6k−3

​  

=0

⇒6k=3

⇒k=  

2

1

​  

 

the ratio is 1:2

Answer 2

We know that

x = M1x2 +M2x1/M1+ M2

And

y = M1y2 + M2y1/M1 +M2

But we know that y=0

So

0 =6M1-3M2/M1 + M2

0 = 6M1 -3M2

-6M1 = -3M2

M1/M2 = 1/2

The ratio is 1 : 2

x = 1*5 +2*2/1+3 = 5+4 /3 =9/3 =3 The coordinate is (3,0)