Question

in what time ₹ 4400 amount to ₹ 4576 at 4% per annum compounded annually?​

Answer 1

$here \\ principle = 4400 \\ time = ... \\ rate \: of \: interest \: = 4\% \\ according \: to \: the \: question \\ 4400 {(1 + \frac{4}{100} )}^{n} = 4576 \\ = > {(1 + \frac{1}{25}) }^{n} = \frac{4576}{4400} \\ = > ({ \frac{25 + 1}{25} )}^{n} = \frac{1144}{1100} = \frac{104}{100} \\ = > {( \frac{26}{25} )}^{n} = \frac{104}{100} \\ = > {1.04}^{n} = 1.04 \\ = > n = 1$

the time is. 1 year ✔✔✔✔

✨✨hope it helps✨✨