Math, asked by om420955, 4 months ago

In what time will ₹ 10000 amount to ₹ 12000, if simple interest reckoned at 8% per annum​

Answers

Answered by supriyasahu
2

Answer:

Principle(P)=Rs.10000.

Amount(A)=Rs.12000.

Simple Interest (S.I.)=A-P

=Rs.(12000-10000)

=Rs.2000

Rate (R)=8%.

Time (T)=??

T=(I*100)/(P*R.)

T=(2000*100)/(10000*8)

T=5/2 years.

T=2 years 6 months.

Step-by-step explanation:

HOPE THIS WILL HELP YOU:)

Answered by cstar21
0

Step-by-step explanation:

12000-10000=2000

intrest =( p \times t \times r) \div 100

2000 = (10000×t×8)÷100

2000=800t

20=8t

10=4t

5=2t

t=2.5

time = 30months

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