Question

In what time will ₹ 4000 amount to ₹5290 at 15% per annum interest compounded annually?

Answer 1

Answer:

Let the time be x.

amount= Rs. 5290

∴ 5290= 4000( 1 + 15/100)ˣ

5290/4000=(115/100)ˣ

529/400=(23/20)ˣ

23²/20²=23ˣ/20ˣ

∴the value of x=2

time = 2 years

Answer 2

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!!}}}$

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Here is your answer
P = Rs 4000
A = Rs 5290
R = 15%
T = t (let)

As we know the formula
A = P (1+R/100)^t
$5290 = 4000(1 + \frac{15}{100} ) {}^{t} \\ \frac{5290}{4000} = ( \frac{100 + 15}{100} ) {}^{t} \\ \frac{529}{400} = ( \frac{115}{100} ) {}^{t} \\ ( \frac{23}{20} ) {}^{2} = ( \frac{23}{20} ) {}^{t} \\ as \: same \: base \: power \: is \: equal \\ 2 = t \\ t = 2 \: years$
Therefore Time is 2 years

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