In what time will rs.1000 amounts to rs.1331 at 20% per annum, compounded half yearly?
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Compound interest accumulation factor :
P × (1 + i)ⁿ
P = amount deposited = 1000
i = interest rate = 20/2 = 10 — compounded semiannually
n = Time
Accumulated amount = 1331
Doing substitution :
1331 = 1000 × (1.10)ⁿ
1331/1000 = (1.10)ⁿ
1.331 = (1.10)ⁿ
Log 1.331 = n log 1.10
0.124178 = 0.041393n
n = 0.124178/0.041393 = 2.999975
= 3 periods
3/2 = 1.5 years
This is because it is compounded semiannually
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