In what time will rupees 1000 becomes Rs.1331 at 10%rate p.a. compound interest.
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C. I = p(1+r/100)- 1
1331= 1000(110/100)^n
1331/1000=(110/100)^n
(11/10)³=( 11/10)^n
Bases are same then power will be added
n = 3 years
1331= 1000(110/100)^n
1331/1000=(110/100)^n
(11/10)³=( 11/10)^n
Bases are same then power will be added
n = 3 years
Answered by
3
Sorry for bad handwriting :-(
Hope it helps
Hope it helps
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