in which case there is a more power dissipation
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The most straightforward way to reason about this doesn't require much math.The power delivered by the voltage source to either pair of resistors is inversely proportion to their combined resistance, i.e, if the combined resistance is greater, the power delivered is smaller.
pR=V2R
Now, recall that:
the series combination of two resistances is always greater than either individual resistancethe parallel combination of two resistances is always less than than resistance of either individual resistance
hope these will help you.....
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