Question

In which of the following 6.02*10^22 molecules are present
a. 2.8 g of N2
b. 1.6 g of O2
c. 4.6 g of Na
d. 1.4 g of O2

Answer 1

Answer:

a.2.8 g of N2

Explanation:

because number of mole =2.8÷28=0.1 mol

number of molecules=0.1×6.022×10^23=6.022×10^22