Physics, asked by GPranavC, 1 year ago

In which of the following cases more electric energy is consumed per hour? (a) a current of 1 ampere passed through a resistance of 300 ohms (b) a current of 2 amperes passed through a resistance of 100 ohms.

Answers

Answered by Anonymous
19

Answer:

a) Electrical energy = 0.3 kWh

b) Electrical energy = 0.4 kWh

Explanation:

To find :

In which of the following cases more electric energy is consumed per hour?

(a) current of 1 ampere passed through a resistance of 300 ohms

(b) a current of 2 amperes passed through a resistance of 100 ohms.

Solution

Let us consider case A

(A) I = 1 A

R = 300 ohms

Power = resistance * current

P= 300 X 1 = 300 W

= 300/1000

= 0.3 kW

Electrical energy = PowerX time

= 0.3 X 1

= 0.3 kWh

Let us consider case But

(B) I= 2A

R= 100 ohms

Power= Resistance*current

P= 100 X 4

= 400 W

= 400/1000

= 0.4 kW

Electrical energy = 0.4 kW X 1

= 0.4 kWh

Answer:

a) Electrical energy = 0.3 kWh

b) Electrical energy = 0.4 kWh

Answered by Nipunmisra
5

Answer:

a) Electrical energy = 0.3 kWh

b) Electrical energy = 0.4 kWh

Explanation:

To find :

In which of the following cases more electric energy is consumed per hour?

(a) current of 1 ampere passed through a resistance of 300 ohms

(b) a current of 2 amperes passed through a resistance of 100 ohms.

Solution

Let us consider case A

(A) I = 1 A

R = 300 ohms

Power = resistance * current

P= 300 X 1 = 300 W

= 300/1000

= 0.3 kW

Electrical energy = PowerX time

= 0.3 X 1

= 0.3 kWh

Let us consider case But

(B) I= 2A

R= 100 ohms

Power= Resistance*current

P= 100 X 4

= 400 W

= 400/1000

= 0.4 kW

Electrical energy = 0.4 kW X 1

= 0.4 kWh

Answer:

a) Electrical energy = 0.3 kWh

b) Electrical energy = 0.4 kWh

Read more on Brainly.in - https://brainly.in/question/3615535#readmore

Explanation:

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