Question

In which of the following cases work done by a force is maximum: when the angle between direction of force and direction of motion is 0o or 900? explain your answer?

Answer 1

Answer:

Work done(W) = FsCosθ

where θ is the angle between Force(F) and displacement(s). Hence work done will be maximum when Cosθ is maximum, which is at θ = 0 and Cosθ = 1.

Hence work done is maximum when θ is at zero degree.

Explanation:

hope it helps you : )

Answer 2

$\red\checkmark\:\:\bf\green{Work\:done\:by\:a\:force\:is\:maximum\:when\:\atop{angle\:bet^n\:direction\:of\:force\:\&\:motion\:is\:0°.}}$

ЄҲƤԼƛƝƛƬƖƠƝ ;-

$\bf\blue{We\:know\:that,}$

$\red\bigstar\:\:{\color{pink}{\boxed{\boxed{\bf{\color{peru}Work\:done\:=\:F\:.\:s}}}}}$

$\bf\purple{Where,}$

• F be the force.

• s be the displacement or motion.

$:\implies\:\:\bf{Work\:done\:=\:F\:s\:\cos{\theta}}$

ƇƛƧЄ - 1

☆ Putting θ = 0° in the above equation, we get

$:\implies\:\:\bf{Work\:done\:=\:F\:s\:\cos{0°}}$

$:\implies\:\:\bf{Work\:done\:=\:(F\:s)\times{1}}$

$:\implies\:\:\bf\orange{Work\:done\:=\:F\:s}$

ƇƛƧЄ - 2

☆ Putting θ = 90° in that above equation, we get

$:\implies\:\:\bf{Work\:done\:=\:F\:s\:\cos{90°}}$

$:\implies\:\:\bf{Work\:done\:=\:(F\:s)\times{0}}$

$:\implies\:\:\bf\green{Work\:done\:=\:0}$

_________________

$\bf\pink{Hence,}$

✔ From the above two cases, we find that work done is maximum in case - 1.

$\bf\orange{Therefore,}$

☆ Work done by a force is maximum, when angle between direction of force & motion is 0°.