Question

in which of the following compounds chlorine exhibits highest oxidation state
(a) Kclo4
(b) Ba(clo2)2
(c) Hoclo2
(d) cl2o6

Answer 1

a is the answer
it exhibits +7 oxidation state

Answer 2

In (a) KClO4, chlorine exhibits the highest oxidation state.

The oxidation state of chlorine in $KClO_{4}$:

• Let x be the oxidation state of chlorine in $KClO_{4}$.
• Now,  1 + x + (−2) × 4 = 0 ⇒ x = +7

The oxidation state of chlorine in $Ba(ClO_{2} )_{2}$:

• Let x be the oxidation number of Cl in $Ba(ClO_{2} )_{2}$.
• The oxidation numbers of Ba and O are +2 and −2 respectively.
• Since the overall charge on the complex is 0, the sum of oxidation states of all elements in it should be equal to 0.
• Therefore, +2+2(x+2(−2))=0
• +2 +2 (x − 4) = 0
• +2 + 2x − 8 = 0
• 2x = +6
• x = +3

The oxidation state of chlorine in $HClO_{2}$:

• Oxidation number of H = +1.
• 1 H atom: (1)*(+1) = +1
• Oxidation number of O is -2.
• 2 O atoms: (2)*(-2) = -4
• Therefore, the oxidation state of Cl is +3.

The oxidation state of chlorine in $Cl_{2} O_{7}$:

• Let x be the oxidation number of Cl in $Cl_{2} O_{7}$.
• 2x + 7*(-2) = 0
• 2x -14 = 0
• x = +7

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