Question

in which of the following situations does the list of number involved make an arithmetic progression and why? (1)the taxi fare after each km when the fare is ₹15 for the First km and and ₹8 for each additional km.
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Answer 1

Answer:

Step-by-step explanation:

F1=Taxi fare in 1st hr=Rs 15

F2=in 2nd fare=Rs 8

F3=3rd hr  fare=Rs 8

F2-F1=8-15=-7

and F3-F2=8-8=0

Thus the common difference is not same so it is not an AP

Answer 2

Answer:

We can write the given condition as;

Taxi fare for 1 km = 15

Taxi fare for first 2 kms = 15+8 = 23

Taxi fare for first 3 kms = 23+8 = 31

Taxi fare for first 4 kms = 31+8 = 39

And so on……

Thus, 15, 23, 31, 39 … forms an A.P. because every next term is 8 more than the preceding term.

Step-by-step explanation:

Hope this helps you ✌️