Question

What is the sum of the first 50 consecutive normal numbers​

Answer 1

Answer:

1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35+36+37+38+39+40+41+42+43+44+45+46+47+48+49+50

= 1275

Hope it helps!!!!!!!...

Answer 2

Answer:

1275

Step-by-step explanation:

There’s a formula to calculate the sum of the first n natural numbers:

(n(n+1))/2

This formula is derived from the formula n/2(2a+(n-1)d)

we take n as 50:

(50(50+1))/2

=(50(51))/2

=(2550)/2

=1275

So, the sum of the first 50 natural numbers is 1275.

You can also use the regular formula [n/2(2a+(n-1)d) ] to calculate this.

For that,

a = 1

d = 1

Thus, 50/2(2(1)+(50-1)1)

= 25(2+49)

=25 x 51

=1275

Hope it Helps!!!!

Hope it helps!