Question

In which of the following tetrahedral geometry is found ?
(A) [Ni(CN), 12-
(B) [Pd(CN),12-
(0) [PdC1,12-
(D) [Nici,2-​

Answer 1

Answer:

i think option B is correct

Answer 2

Tetrahedral geometry is found in [NiCl4](2-).

• In all the complexes listed here the metal ions Ni(2+) has a 3d8 electronic configuration while Pd(2+) has a 4d8 electronic configuration.
• The complex will be square planar if pairing of electrons take place for a d8 electronic configuration or else it will be tetrahedral.
• All donor species can enable pairing in case of Pd(2+) since the energy gap is lower for 4d and 5d series.
• In 3d series, CN- acts as a strong field donor species while Cl- acts as a weak field donor species, hence Cl- cannot enable pairing of electrons in case of  [NiCl4](2-).

• Therefore  [NiCl4](2-) is tetrahedral while the other three complexes are square planar.