Math, asked by TbiaSupreme, 1 year ago

In ΔXYZ and ΔPQR, XYZ ⇔ PQR is similarity. XY=12, YZ=8, ZX=16, PR=8.So, PQ+QR= ......,select a proper option (a), (b), (c) or (d) from given options so that the statement becomes correct.
(a) 20
(b) 10
(c) 15
(d) 9

Answers

Answered by abhi178
8
we know by definition, for a given correspondence between the vertices of two triangles, if the corresponding angles of the triangles are congruent and the lengths of the corresponding sides are in proportion, then the given correspondence is a similarity between two triangles.

here XYZ ⇔ PQR is similarity,
then, XY/PQ = YZ/QR = XZ/PR
XZ/PR = XY/PQ = YZ/QR = (XY + YZ)/(PQ + QR)
XZ/PR = (XY + YZ)/(PQ + QR)

Given, XY=12, YZ=8, ZX=16, PR=8.
so, 16/8 = (12 + 8)/(PQ + QR)
2 = 20/(PQ + QR)
PQ + QR = 10

hence, option (b) is correct.
Answered by Anonymous
4

Answer:

PQ+QR = 10

hope it helps you✌

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