Question

In ydse the distance between two identical slit is 6.1 times larger than the slit width .Then the number of intensity maxima obserbsed within the central maximum of the single slit diffraction pattern is

Answer 1

The number of intensity maxima obserbsed within the central maximum of the single slit diffraction pattern is approximately 12.

Explanation:

=> Width of central maxima in single slit:

w = 2(Dλ/a)

For Young's double slit experiment,

width of bright fringe = Dλ/d

=> Suppose n maxima lies in central maxima.

According to the question, the distance between two identical slit is 6.1 times larger than the slit width. (∴ d = 6.1)

n (Dλ/d) = 2Dλ/a

n = 2Dλ * d / Dλ * a

n = 2d / a

  = 2 * 6.1 * a / a

  = 12.2

  ≈ 12

Hence, the number of intensity maxima obserbsed within the central maximum of the single slit diffraction pattern is approximately 12.

Learn more:

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