Question

in year 2001 the price of article a is 20% more than price of article b. in year 2002 price of article a is 50% greater than price of a. from 2001-02 if the price of a has increased by 50% then by what per cent the price of b increased
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Answer 1

Answer:

In 2001 year

Let the price of B be x

Theb the price of A will be(x+10020×x)=1.2x

In 2002 year

Let the price of B bey

Then the price of A will be(y+y×10050)=1.5y

According to question

1.5y=1.2x(1+0.5)⇒1.5y=1.2x+.6x⇒1.5y=1.8x

For article B

⇒y=56xy=1.2x=(1+0.2)x

The price of B increased by 20% from 2001 to 2002 year.

Answer 2

Answer:

In 2001 year

Let the price of B be x

Theb the price of A will be

(x+

100

20

×x)=1.2x

In 2002 year

Let the price of B be

y

Then the price of A will be

(y+y×

100

50

)=1.5y

According to question

1.5y=1.2x(1+0.5)

⇒1.5y=1.2x+.6x

⇒1.5y=1.8x

For article B

⇒y=

5

6

x

y=1.2x=(1+0.2)x

The price of B increased by 20% from 2001 to 2002 year.