Question

In Young's double slit experiment, a glass plate is placed before a slit which absorbs half the intensity of light. Under this case(a) The brightness of fringes decreases(b) The fringe width decreases(c) No fringes will be observed(d) The bright fringes become fainter and the dark fringes have finite light intensity

Answer 1

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Answer 2

Answer:

d) The bright fringes become fainter and the dark fringes have finite light intensity

Explanation:

As a glass plate is placed before the slit which absorbs half the intensity of light so

The pattern for bright fringes becomes fainter because the wave does not constructively interfere so the intensity of light as absorbed by the glass plate the bright fringe becomes fainter.

Now for dark fringe it makes a destructive interference which in result the value of (2n-1) increases so the dark fringes have finite light intensity.