Question

In the Young's double slit experiment, the spacing between two slits is 0.1 mm. If the screen is kept at a distance of 1.0 m from the slits and the wavelength of light is 5000 Å, then the fringe width is(a) 1.0 cm(b) 1.5 cm(c) 0.5 cm(d) 2.0 cm

Answer 1

. ....( lemda ) × D
B = ------------------
............... .d
= 5000 × 10^ (-10) × 1
.....--------------------------
.......... 0.1× 10^(-3)
= 5 mm