in young's double slit experiment light has a frequency of 6x10^14Hz. the distance between the centers of adjacent bright fringes is 0.75mm if the screen is 1.5m away then find the distance between the slits.{PLZ GIVE THE SOLUTION ASAP}
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Answered by
59
first we find wavelength
velocity of light=wavelength x frequency
3 x 10^8= wavelength x 6 x 10^14
wavelength =3 x 10^8/6 x10^14
=1/2 x10^-6 =5 x 10^-7m
given distance between adjacent bright fringe =0.75mm=wavelength x D/d
where D is distance between slit and screen , d is the distance between two slit .
now ,
0.75 x10^-3=(5x 10^-7 x1.5 )/d
d=(7.5 x 10^-7)/(7.5 x 10^-4)
=10^-3
hence 1mm is the distance between slits .
velocity of light=wavelength x frequency
3 x 10^8= wavelength x 6 x 10^14
wavelength =3 x 10^8/6 x10^14
=1/2 x10^-6 =5 x 10^-7m
given distance between adjacent bright fringe =0.75mm=wavelength x D/d
where D is distance between slit and screen , d is the distance between two slit .
now ,
0.75 x10^-3=(5x 10^-7 x1.5 )/d
d=(7.5 x 10^-7)/(7.5 x 10^-4)
=10^-3
hence 1mm is the distance between slits .
abhi178:
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Answered by
8
Fringe width=D×lamda/d
0.75×10^-3= 6×10^14×1.5/7.5×10^-4
=9×10^10/7.5
=1.28×10^10
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