In Young’s double slit experiment, light of 500 nm produces fringes 5 mm apart. What would
the fringe spacing be if you use light of wavelength 250 nm instead ?
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Answer:
Fringe width (β)=
d
Dλ
=
1.2×10
−3
5.4×500×10
−9
=22.5×10
−4
=2.25×10
−3
m
Explanation:
2.25 × 10-³m
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