Physics, asked by saumyasingh338, 9 months ago


In Young's double slit experiment, the separation between the two slits is
halved. The new fringe width will be ___ __times its initial value.​

Answers

Answered by aman7913
2

Question:

In Young's double slit experiment, the separation between the two slits is

halved. The new fringe width will be ___ __times its initial value.

Answer:

Quadrupled

_________________________________

Answered by muscardinus
0

The new fringe width will become twice of the initial fringe width.

Explanation:

In Young's double slit experiment, the fringe width is given by formula as :

\beta =\dfrac{\lambda D}{d}

Here,

\lambda is wavelength

D is distance of screen and source

d is the separation between the two slits

It is clear that the fringe width is inversely proportional to the separation between the two slits. In this case, it is mentioned that if the separation between the two slits is  halved. So, the new fringe width will become twice of the initial fringe width.

Learn more,

Young's double slit experiment

https://brainly.in/question/7560303

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