Question

In Young’s experiment , the distance of screen from the two slits is 1.0m. When light of wavelength 6000 Angstrom is made incident ,fringes of width 2.0mm are obtained on the screen. Calculate : (i) the distance between the slits, (is) the fringe width if the wavelength of incident light is 4800 Angstrom​

Answer 1

Answer:

All bright and dark fringes are of equal width.

Fringe width is given by

β=dDλ

where d is separation between slits,

D is distance between slit and screen,

λ is wavelength of monochromatic light.

Here, λ=6000A˚=6000×10−10m

D=25cm=25×10−2m

d=1mm=1×10−3

Hence, β=1×10−36000×10−10×25×10−2

=1.5×10−4

=0.15×10−3m=0.15mm