Question

Two blocks of masses 8 kg and 2 kg respectively lie on a smooth horizontal surface in contact with one other. They are pushed by a horizontally applied force of 15N .Calculate the force exerted on the 2 kg mass​

Answer 1

AnsWer :

3N.

GiveN :

• Two blocks of masses 8 kg and 2 kg respectively lie on a smooth horizontal surface in contact with one other.
• Fnet = 15N.

SolutioN :

Let,

• Block mass m1 = 8 kg.
• Block mass m2 = 2 kg.
• Fnet = 15N.

★ We have Formula.

$\tt \dagger \: \: \: \: \: F_{net} = ma.$

Where as,

• F ( Force )
• M ( mass of block )
• a ( acceleration )

Taking Block first ( m1 )

• Block m1 = 10N.

$\tt : \implies F_{net} = ma.$

$\tt : \implies15= 10a.$

$\tt : \implies a = \dfrac{15}{10} .$

$\tt : \implies a = 1.5m \: {s}^{2} .$

Now, Taking Block second ( m2 )

• Block M2 = 2 kg.

$\tt : \implies F_{net} = ma.$

$\tt : \implies F_{net} = 2 \times 1.5.$

$\tt : \implies F_{net} = 3n.$

Therefore, the force exerted on the 2 kg mass is 3N.