Question

In zero order reaction 20% of the reaction completed in 10 second how much time it will take to complete 50% of the reaction

Answer 1

Answer:

It will take 25 seconds to complete 50% of the reaction.

Explanation:

let the initial concentration =$A_o$

Concentration left at after 10 seconds ,$A=(100\%-20\%)A_o=80\%A_o=0.8A_o$

Integrated rate law for Zero order kinetics:

$k=\frac{1}{t}[A_o-A]$

Rate of the reaction:

$k=\frac{1}{10}[A_o-0.8A_o]=0.02 A_o$

Time taken by the reaction to get completed by 50%.

let the initial concentration =$A_o$

Concentration left at after t' seconds ,$A=(100\%-50\%)A_o=50\%A_o=0.5A_o$

$0.02 A_o=\frac{1}{t'}[A_o-0.5A_o]$

t' = 25 seconds

It will take 25 seconds to complete 50% of the reaction.

Answer 2

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