Question

Ina A ball is thrown in a upward direction with the velocity 20m/s . Find the maximum height after 5s at its highest point,​

Answer 1

Answer:

Explanation:

Given, initial velocity, u=5ms−1

Final velocity, v=0

Since, u is upward & a is downward, it is a retarded motion.

∴a=−10ms−2

Height attained by stone, s=?

Time take to attain height, t=?

(i) Using the relation, v2−u2=2as, we have

s=v2−u2/2a

=(0)2−(5)2/2×(−10)=1.25m

(ii) Using the relation, v=u+at

0=5+(−10)t or

t=5/10=0.5s

Answer 2

answer is 100 meters high