Ina A ball is thrown in a upward direction with the velocity 20m/s . Find the maximum height after 5s at its highest point,
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Answer:
Explanation:
Given, initial velocity, u=5ms−1
Final velocity, v=0
Since, u is upward & a is downward, it is a retarded motion.
∴a=−10ms−2
Height attained by stone, s=?
Time take to attain height, t=?
(i) Using the relation, v2−u2=2as, we have
s=v2−u2/2a
=(0)2−(5)2/2×(−10)=1.25m
(ii) Using the relation, v=u+at
0=5+(−10)t or
t=5/10=0.5s
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answer is 100 meters high
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