Question

Ina box, there are 9 red, 4 blue and 3 black. One ball is picked up randomly. The probability

getting neither red nor black is a/32 . What is ‘a’

Answer 1

Step-by-step explanation:

Total number of balls = (8 + 7 + 6) = 21

Let E = event that the ball drawn in neither red nor green

= even that the ball drawn in blue.

∴n(E)=7

∴P(E)=

n(S)

n(E)

=

21

7

=

3

1

hope it helps

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Answer 2

Answer:

=150 are equal a present ball