Question

Ina house 2 bulbs of 50W each are used for 4 hours a day 2 fans of 50W each are used for 10 hours a day . Calculate the unit of elextricity consumed in a month of 30 days.

Answer 1

Bulbs :-

Number of bulbs = 2

Power of each bulb = 50 watt

Power (in kW) = 0.05 kW

Time of usage = 4 hours a day

Energy consumed by each bulb in one day will be :-

$4 \times 0.05 = 0.2kwh$

Total energy consumption by two bulbs in one day is

$2 \times 0.2 = 0.4kwh$

Energy consumption in 30 days will be:-

$30 \times 0.4 = 12kwh$

$\rule{200}{4}$

Fans:-

Number of fan = 2

Power of each fan = 50 watt

Power (in kW) = 0.05 kW

Time of usage = 10 hours a day

Energy consumed by each fan in one day will be :-

$0.05 \times 10 = 0.5kwh$

Energy consumed by two fans will be 1kwh

Energy consumption in 30 days will be :-

$1 \times 30 = 30kwh$

$\rule{200}{4}$

Total energy consumption by two things will be :-

$12 + 30 = 42kwh$

$\rule{200}{4}$

We know that

$1 \: unit = 1kwh$

Thus,

Total energy consumption in 30 days will be as follows :-

$= 42 \: units$

$\rule{200}{4}$