Question

ina selenoid of 2 m there r 1000turns and current of 10A is passing through it find the magnetic field at centre of solenoid​

Answer 1

We know that the magnetic field of a solenoid is (u°ni/2r)

Where n is the no of turns, r is the radius, i is the current and u° is the permeability of vacuum.

= (u°ni/2r)

= (4π x 10^(-7) x 10^3 x 10)/2 x 2

= π x 10^(-7) x 10^4

= π x 10^(-3) Tesla