ina selenoid of 2 m there r 1000turns and current of 10A is passing through it find the magnetic field at centre of solenoid
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We know that the magnetic field of a solenoid is (u°ni/2r)
Where n is the no of turns, r is the radius, i is the current and u° is the permeability of vacuum.
= (u°ni/2r)
= (4π x 10^(-7) x 10^3 x 10)/2 x 2
= π x 10^(-7) x 10^4
= π x 10^(-3) Tesla
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