#include <stdio.h>
int main()
{
int i = 3;
int i = i/-2;
int k = 1 %-2;
printf("%d %d\n",1,k);
return 0;
}
Answers
Answered by
2
Answer:
It will generate an error
Explanation:
on line 4 you have created integer I
and on line 5 your modifieng its value ...
but here you've re typed int which generates an error ...
please mark me as brailiest ...
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