Computer Science, asked by nandini2000r, 20 days ago

include<stdio.h>
void call(int num)
{ int count = 15;
while (count > 0)
{
if (num % 3 == 4);
{
count count - 3;
}
else if (num % 3 == 1)
count = count - 1;
}
else
{
count = count -2;
}
num++;
}
print("%d",num);
}
int main()
{
int x=23;
call(x);
return 0;
}​

Answers

Answered by madeducators2
0

Answer:

32

Given:

#include <stdio.h>

void call(int num)

{ int count = 15;

while (count > 0)

{

if (num % 3 == 4)

{

count= count - 3;

}

else if (num % 3 == 1)

{count = count - 1;

}

else

{

count = count -2;

}

num++;

}

printf("%d",num);

}

int main()

{

int x=23;

call(x);

return 0;

}

Explanation:

  • Here the functions call is executed with num=23 and count =15
  • Then according to the given function count is decreased and num is increased till the value of count reaches 0 and the function call terminates when num is 32

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