Question

The factorisation off (2a-3b)³+(b-2c)³+8(c-a)³ is​

Answer 1

Answer:

Solution

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Correct options are A) , B) and C)

a  

3

+b  

3

+c  

3

−3abc=(a+b+c)(a  

2

+b  

2

+c  

2

−ab−bc−ca)  

So, if a+b+c=0, a  

3

+b  

3

+c  

3

=3abc

The given expression can be written as  

(2a−b)  

3

+(b−2c)  

3

+(2c−2a)  

3

 

We can see here that 2a−b+b−2c+2c−2a=0.

Hence, following the above concept

(2a−b)  

3

+(b−2c)  

3

+(2c−2a)  

3

=6(2a−b)(b−2c)(c−a)

Hence, options A, B, C are correct.

Step-by-step explanation:

Answer 2

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